分式和整数指数幂计算题
(1)x 2y -3(x -1y ) 3
(2)(2ab 2c -3) -2÷(a -2b ) 3
(3)20090+(-2) -3+(-1
) 32+(-3) -2
(4) (-1) 2+(12
) -1-5÷(2010-π) 0
(5)⎡-3-12
⎣-2-8⨯(-1) ⎤⎦⨯(-
12
2
)
-⨯7
(7)-m
2
⎛n 2
⎫m n ÷ ⎝m 3⎪⋅⎭n
2
(8)4a 4b 4
15x
3
⋅
35x
2
-8a 3
b
2
(9)x 2
-x
x -3
x 2
-6x +9⋅
x
(10)a -b ab -a
2
a 2
+ab
÷
a 2
b 2
-a
4
(11)11x -1
+
x +1
(12)
x -y 2
-y
2
2y
x +3y
÷
x x
2
+6xy +9y
2
-
x +y
(13)(2x )2·(
3y 31
3y
4x
)÷(4
xy )
x
2
2
(14)(-)2
·(-
y
)3÷(-
y 4y
x
x
)
(15) (
a +2a a 2
-2a
-
a -1a 2
-4a +4
) ⋅
a -24-a
÷
a
2
先化简再求值:a =2-3
x 2
-2x (16)
(x -
x x +1
) ⋅
x +1x 2
+4x +4
÷
x 2
-4
,其中x =-
12
。
(17)计算:
2x -62
x+3)·
x +x -64-4x +x
2
÷(3-x
, 求x=-2时的值.
分式和整数指数幂计算题
(1)x 2y -3(x -1y ) 3
(2)(2ab 2c -3) -2÷(a -2b ) 3
(3)20090+(-2) -3+(-1
) 32+(-3) -2
(4) (-1) 2+(12
) -1-5÷(2010-π) 0
(5)⎡-3-12
⎣-2-8⨯(-1) ⎤⎦⨯(-
12
2
)
-⨯7
(7)-m
2
⎛n 2
⎫m n ÷ ⎝m 3⎪⋅⎭n
2
(8)4a 4b 4
15x
3
⋅
35x
2
-8a 3
b
2
(9)x 2
-x
x -3
x 2
-6x +9⋅
x
(10)a -b ab -a
2
a 2
+ab
÷
a 2
b 2
-a
4
(11)11x -1
+
x +1
(12)
x -y 2
-y
2
2y
x +3y
÷
x x
2
+6xy +9y
2
-
x +y
(13)(2x )2·(
3y 31
3y
4x
)÷(4
xy )
x
2
2
(14)(-)2
·(-
y
)3÷(-
y 4y
x
x
)
(15) (
a +2a a 2
-2a
-
a -1a 2
-4a +4
) ⋅
a -24-a
÷
a
2
先化简再求值:a =2-3
x 2
-2x (16)
(x -
x x +1
) ⋅
x +1x 2
+4x +4
÷
x 2
-4
,其中x =-
12
。
(17)计算:
2x -62
x+3)·
x +x -64-4x +x
2
÷(3-x
, 求x=-2时的值.